陷入困境的复合IF声明

Question

I am experienced programmer, but am not a PHP developer. I have been asked to troubleshoot the following code, but can't see what the problem is. This IF statement works:

<?php
    if ($ice_cream_social == 'yes') {
        $registration_price = "58.00";
    }
?>

However, the page in question requires some compound IF statements to test if form elements have been checked and adjust the price accordingly. This code does NOT work, it doesn't give an error -- but the IF doesn't execute:

<?php
    if ($ice_cream_social == 'yes' AND $registration_type == 'Banquet and Conference') {
        $registration_price = "78.00";
?>

Using developer tools I have verified the form fields are being passed from the HTML, the code has the variable name and value spelled correctly, and I can test for any ONE variable's value successfully. It seems that when a second or third test is added using the syntax I showed above, the test fails and the IF doesn't run. Based on my limited understanding of PHP's syntax and some Googling, the code looks correct to me (and does not produce any errors), but I am thinking I am missing something about why this isn't working.

Can someone tell me if I'm missing something obvious in my code sample that would cause the IF not to run? I didn't include more code as this is one piece of a messy set of includes :)

Thanks!

Answer 1

It looks like to me on the elseif you don't have a logical check, so you either need to change it to else or add a check(if that is your intention) elseif($registration_price>0)

I used this code to test:

<?php
$registration_price = '';
$ice_cream_social = 'yes';
//$ice_cream_social = 'no';
$registration_type = 'Banquet and Conference';
//$registration_type = 'Something else';

if ($ice_cream_social == 'yes') {
    $registration_price = "58.00";
} else {
    $registration_price = "not defined";
}        
echo $registration_price;

if ($ice_cream_social == 'yes' && $registration_type == 'Banquet and Conference') {
    $registration_price = "78.00";
} elseif( 1 > 0) {
    $registration_price = "1 million dolars!";
} else {
    $registration_price = "not defined";
}

echo $registration_price;