dou72260 2013-10-03 23:20
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单个变量中的多个数据库行值

I am adding all names in to single variable but it is showing only one value last one.

my code is:

include 'dbconnect.php';
$result = mysql_query("SELECT * FROM bookedtates WHERE SID='$ServiceHosterIdv' AND BOOKEDDATE='$q'");
//$result = mysql_query("SELECT * FROM bookedtates WHERE SID='$ServiceHosterIdv' AND BOOKEDDATE='$q'");
while ($row = mysql_fetch_assoc($query)) {
$csk = "'".$row['NAME']."',";
}
echo $csk; 
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3条回答 默认 最新

  • douchuanchai2793 2013-10-03 23:22
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    No u just assign variable use it to plus add a "." before equtaion

      $csk .= "'".$row['NAME']."',";
    

    But I would suggest to use array so u can use for JS(if ajax) or php for more flexible things

    $csk = array();
    while ($row = mysql_fetch_assoc($query)) {
    $csk[] = array($row['NAME']);
    }
    echo $csk; //for ajax use echo json_encode($csk);
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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