dshm8998473 2013-08-13 13:16
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将AJAX变量传递到.php页面并加载该页面和echo变量

Simple question: I just want to send item_num to insert_profile.php, then load insert_profile.php and echo out item_num there. It's not working! 'insert_profile.php' will load but it's not getting the data.

Is it a problem with my data:? I've also tried data: {item_num: item_num}. I'm sorry if this is a duplicate, but I've tried all of the examples I've seen and none of them are working. I think it could also be in success:

I've also looked at http://api.jquery.com/jQuery.ajax/.

Javascript/HTML

 <script>

$('.prof_wl_btn').click(function() { 
$(this).removeClass('prof_wl_btn');
$(this).addClass('prof_wl_btn_added');
  var item_num = this.id;
  alert('item id    ' + item_num); //*this will alert correctly*
  $.ajax({
      type: "POST",
      url:'insert_profile.php',
      data: "item_num"+item_num,   
      success: location.href = "insert_profile.php" //*this will load**   
  });
});
</script>

PHP

<?php
$s_n = $_REQUEST['item_num'];
echo $s_n;
?>
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2条回答 默认 最新

  • duanpo8329 2013-08-13 13:31
    关注

    You can't echo the variable this way because you have two different requests for the same page:

    • The first is the AJAX request when you send the data to your page where you do some action and the return;
    • The second one when you access insert_profile.php page, when your value is lost.

    If you want to see that your value is echoed you can do this:

    The AJAX call should look like:

        $.ajax({
          type: "POST",
          url:'insert_profile.php',
          data: {item_num : item_num},   
          success : function(data) {
             alert(data);  
          }
      });
    

    Then your PHP file:

    <?php $s_n = $_POST['item_num']; 
      echo $s_n;
      exit;
    ?>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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