if ( isset( $_POST['add'] ) ) {
$id = $sql['id'];
$sql = "SELECT * FROM table1 WHERE id IN (id1, id2, ..., idn)";
$insert = "INSERT INTO table1(firstname,lastname,birthday,numbers,numbers2,aadress,vali) VALUES('$firstname','$lastname','$birthday','$number','$capture_field_vals1','$aadress','$vali')";
$insert2 = "INSERT INTO table2(number1, number2, number3, number4, number5, number6, number7, number8, number9, number10) VALUES('" . $capture_field_vals[0] . "','" . $capture_field_vals[1] . "','" . $capture_field_vals[2] . "','" . $capture_field_vals[3] . "','" . $capture_field_vals[4] . "','" . $capture_field_vals[5] . "','" . $capture_field_vals[6] . "','" . $capture_field_vals[7] . "','" . $capture_field_vals[8] . "','" . $capture_field_vals[9] . "')";
$insert3 = "INSERT INTO table2 (contactID) VALUES ('$id')";
//$sql.= " WHERE id = '$id' ";
if(mysql_query($insert)) {
//echo "$eesnimi $perenimi ON $aastad AASTAT VANA";
} else {
//echo "Cannot Insert";
}
if(mysql_query($insert2)) {echo "KORRAS";} else {echo "Cannot Insert";}
if(mysql_query($insert3)){echo 'KORRAS';} else{echo 'Cannot Insert';}
}
Question is, how do I get table1 ID into table2 contactID ?
I tried a lot with different ways, but no output..