从ajax运行php

Question

i have a countdown timer when it finish it run a php script (file called ajax.php) the problem is the ajax.php run many times .

i want to get this result in the table

[id][content]
[1][timer]

---

but i get this result

[id][content]
[1][timer]
[2][timer]
[3][timer]
[4][timer]
[5][timer]
[6][timer]
[7][timer]
[8][timer]
[9][timer]
.....

this is the code

    <div id="counter"></div>

    <script src="jquery.js"></script>
    <script>
    var div = $('#counter');

    var n = 5000;

    var blured = false;

    var tid = setInterval(function() {
        if (blured) return;    
        n -= 100;
        div.text( (n / 1000).toFixed(1) + ' seconds passed' );
        if ( n <= 0 ) {


        div.text('Time passed!'); 
        $.ajax({

        url: 'ajax.php',
        type: 'post',
        success: function(data, status) {}

        });




        }


    }, 100);

    window.onblur = function() {
        blured = true;    
    };

    window.onfocus = function() {
        blured = false;    
    };


        document.getElementById("progress").innerHTML="<div style=\"width:'.$percent.';background-color:#ddd;\">&nbsp;</div>";
        // document.getElementById("information").innerHTML="'.$i.' row(s) processed.";
        window.onblur = function() {
            blured = true;    
        };
        window.onfocus = function() {
            blured = false;    
        };


    </script>

and this is ajax.php

    mysql_connect("localhost","root","usbw") or die ("Couldn't connect to server");
    mysql_select_db("test") or die ("Coouldn't Select Database");


    $query = mysql_query("INSERT INTO add_delete_record VALUES ('', 'timer')");

Answer 1

    var tid = setInterval(function() {
    if (blured) return;    
    n -= 100;
    div.text( (n / 1000).toFixed(1) + ' seconds passed' );
    if ( n <= 0 ) {


    div.text('Time passed!'); 
  clearTimeout(tid);
    $.ajax({

    url: 'ajax.php',
    type: 'post',
    success: function(data, status) {}

    });




    }


}, 100);