在网站的报废内容中查找特定的字符串模式并替换内容

Question

I have some scrapped content like

<figure><a href="/fzesny/sample.html">
    <img alt="playerpr120x76" src="/assets/small.jpg"><span class="number">1</span>
    <figcaption>Some Name</figcaption></a>

I need to change the href value to "#" and append scrapped contents URL in the image src.

<a href="">

and image tag must have the server URL appended

<img src="www.example.com/assets/small.jpg"

For image i used

$find = "/assets";
$replace = 'http://www.example.com/assets';
echo str_replace($find,$replace,$full_content,$i)

How can i remove the href link ?

Answer 1

You can remove the content of your href tag with preg_replace :

$str= '<a href="some/url/idontwant.html">Hey !</a>';
$str = preg_replace("/href=\".*\"/", "href=\"\"", $str);
echo $str;

Output : <a href=""> Hey !</a>