在PHP中的子字符串后捕获方括号之间的文本

Question

I have string like below which is coming from DB.

$temp=Array(true);
if($x[211] != 15)
    $temp[] = 211;
if($x[224] != 1)
    $temp[] = 211;
if(sizeof($temp)>1) {
    $temp[0]=false;
}
return $temp;

I need to find all the values inside square brackets followed by $x variable. I.e 211 and 224 .

I tried below code which i found in this website as an answer, but it returns all the values in square bracket including the one followed $temp variable.

preg_match_all("/\[(.*?)\]/", $text, $matches);
print_r($matches[1]);

Please let me know how can i get this desired results ?

Answer 1

RegEx

(?<=\$x\[).*(?=\])

Demo

$re = "/(?<=\$x\[).*(?=\])/"; 
$str = "Sample String"; 

preg_match_all($re, $str, $matches);

Explanation

• LookBehind - Matching pattern should come after $x[ --- (?<=\$x\[). If pattern to be matched is XYZ then behind XYZ $X should exist.

• .* match all after the last matching pattern

• LookAhead - (?=\]) - Match all untill ]