PHP IntlDateFormatter ::解析输出时区

Question

I have the following PHP code:

$date = 'janvier 1, 2014 à 5:00PM';
$formatter = new IntlDateFormatter('fr_CA', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Toronto', IntlDateFormatter::GREGORIAN, 'MMMM d, yyyy 'à' h:mma');
$date = $formatter->parse($date);
var_dump($date);

The output is:

int(1388613600)

This appears to be a UNIX timestamp, which is always UTC, Right? So it's automatically being converted from America/Toronto?

Just confirming that I have this correct. I don't have a lot of experience with PHP and time zones, so I appreciate any help.

Answer 1

Correct. The timestamp is a UNIX timestamp. That is - the number of whole seconds since Jan 1, 1970 UTC, not accounting for leap seconds.

You can verify the timestamp using a site like epochconverter.com

1388613600 = 2014-01-01T22:00:00Z

Then you can check the time zone details at timeanddate.com.

• In January 2014, Toronto was on EST, which is UTC-05:00.
• This calculation clearly verifies that 22:00 UTC is 5:00 PM EST.