正则表达式：匹配所有内容：直到或<br />

I would like to change the following text

тест: фыв, фыв <br />
тест: фыв, фыв, фывфыв фыв, фыв, фыв <br />
счет: 123 <br />
высота: 111 <br />
конец: ок <br />

to:

тест: :: фыв, фыв :: <br />
тест: :: фыв, фыв, фывфыв фыв, фыв, фыв :: <br />
счет: :: 123 :: <br />
высота: :: 111::  <br />
конец: :: ок :: <br />

what I've tried:

$text = <<<HTML
    тест<br /><br />тест: фыв, фыв<br />тест: фыв, фыв, фывфыв фыв, фыв, фыв<br /><br />счет: 123<br />высота: 111 <br />конец: ок<br /><br />
HTML;

$text = preg_replace('~(\w+:)\s*(.*?)(\<br /\>|\R)~', '\1 :: \2 :: \3', $text);

echo $text;

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码龄粉丝数原力等级 --

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dplase3140 2014-05-22 07:18
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RegEx:

([^:]+:)\s*(.*?)(<br\s*/>|\R) \1 :: \2 :: \3

PHP:

$row['text'] = preg_replace('~([^:]+:)\s*(.*?)(<br\s*/>|\R)~', '\1 :: \2 :: \3', $row['text']);

Explanation: First ([^:]:) we match and capture 1+ non-colon characters followed by a colon. This is followed by some optional whitespace (\s*). Then we lazily capture 0+ characters (.*?). Finally we capture either the line break (<br\s*/>) or the new line (\R).

Notes: I used ~ delimiters so that we didn't need to escape the / in the line break. We use lazy repetition for the second capture group because it lets us grab everything until the line break or new line.
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