drctyr2869 2014-04-17 05:01
浏览 38
已采纳

Yii中的表单:如果验证失败,如何发回数据

I got this code:

public function actionJoin() {
  $user = new RUser;

  if (isset($_POST['RUser']))
      $user->attributes = $_POST['RUser'];

  $this->render('join',
    array(
        'user' => $user
    )
  );
}

Which will not yet allow user to register. What I want to know is how to send data back to user. I mean, if user form haven't passed verification I have to send some data back, so there is no need for user to re-enter it again.

I can do so with this:

$user->mail = $_POST['RUser']['mail'];

But it's looks like dropping back to plain PHP and not using powers of the framework here.

Addition. Publishing RUser class, if needed:

class RUser extends CFormModel
{
    public $mail;
    public $alias;

    public function safeAttributes()
    {
        return array(
            'mail', 'alias'
        );
    }
} 
  • 写回答

1条回答 默认 最新

  • douyin8809 2014-04-17 05:30
    关注

    Which version of Yii you use. In Yii 1.1, there are no safeAttributes. You use the followings,

    public function rules()
    {
        return array(
            array('mail, alias', 'safe'),
        );
    }
    
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