doudu4282 2014-02-24 16:29
浏览 103
已采纳

使用php / ajax选择下拉列表后,从数据库获取客户信息

i'm trying to make a simple webpage for making invoices. to select/load customer info i'm using a select dropdown filled with all the customers in the database. after selecting a customer i want php to get all the values of that customer from the database and echo somewhere else on the page. thought it would be something simple but tried everything and cant seem to get it to work.

any help?

after deleting all the code that didn't work anyway this is what i'm left with:

<select name="selectCustomer">
    <option selected>Klantnaam</option>
    <?
        $result = mysql_query('SELECT * FROM '.$c_tbl_name);

        while($row = mysql_fetch_array($result)) {
            echo    '<option value="'.$row['c_id'].'">';
            echo        $row['c_name'];
            echo    '</option>';
        }
    ?>
</select>
  • 写回答

2条回答 默认 最新

      报告相同问题?

      相关推荐 更多相似问题

      悬赏问题

      • ¥15 Win7电脑开机出现硬件设置已更改
      • ¥15 vba代出现莫须有错误,都是一个个复制下来的为啥出错呢?
      • ¥15 /etc/vsftpd/vsftp.conf配置文件加了一行utf8_filesystem=YES之后,启动vsftpd报错
      • ¥15 W5100可以收广播,但是无法发出广播
      • ¥100 PCD点云排序和分割
      • ¥15 GG-CNN抓取数据集
      • ¥15 C++类和对象,多态性,继承,虚函数虚基类
      • ¥15 使用VS2019和Dev c++按%p输出地址,结果相差很大
      • ¥30 有偿解惑TINA老报错,求解惑
      • ¥15 arduino esp8266 编译问题