dongrang2186 2013-12-18 14:26
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preg_replace用于替换变量的所有内容

I actually got a problem, in my situation i select information from a MYSQL Database saved into $data.

and i have 2 arrays for preg_replace.

this is an example :

$repl();
$repl[0] = '/bull/';
$repl[1] = '/found/';
$repl[2] = '/search/';

$replto();
$replto[0] = 'This is not a ballon';
$replto[1] = 'This has been found';
$replto[2] = 'Im looking for it';

$data = array();
$data[0] = '/mynickname/search';
$data[1] = '/somebulls/search';
$data[2] = '/mcdo/found';
$data[3] = '/bump/search';
$data[4] = '/blood/bull';

echo preg_replace($repl,$replto,$data);

Ok, but the output of preg_replace is this :

/mynickname/Im looking for it
/somebulls/Im looking for it
/mcdo/This has been found
/bump/Im looking for it
/blood/This is not a ballon

... but I want this output :

Im looking for it
Im looking for it
This has been found
Im looking for it
This is not a ballon

I'm new in php, i solved a lot of problem but this is a problem that i haven't found solution.

Can you help me please?

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2条回答 默认 最新

  • dongxiongshi9952 2013-12-18 14:44
    关注

    Based on the result you want, it looks like you want to do something like:

    $repl();
    $repl[0] = '/.*bull/';
    $repl[1] = '/.*found/';
    $repl[2] = '/.*search/';
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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