drxdn40242 2013-12-18 06:57
浏览 26
已采纳

在搜索脚本中获取错误[php,mysqli]

I am trying to create a very simple and basic search script.

Here is what I have done so far:

include('config.php');

$search_token =$_POST['search_token'];

$search_query = mysqli_query($conn, "SELECT Forname FROM idea WHERE post_des LIKE '%$search_token%'");

while($row = mysqli_fetch_array($search_query))
  {

  $idea_body = $row['post_des'];

  echo $idea_body;
}

But when I execute this, I am having the following Warning:

Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in F:\Server\xampp\htdocs\p\c3\search.php on line 34

Any help for this situation?

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2条回答 默认 最新

  • doudou3935 2013-12-18 07:00
    关注

    You probably have a problem in your query, try:

    $search_query = mysqli_query($conn, "SELECT Forname FROM idea WHERE post_des LIKE '%$search_token%'") or die(mysqli_error($conn));
    

    To debug your query.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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