dongmimeng5500 2013-09-25 15:16
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从同一PHP资源调用多个函数

On my page I'm trying to run two functions from the same .PHP document, however I was getting the error "function already declared".

I had a look here: PHP: how to avoid redeclaring functions?

After looking at this I changed my code to:

            <?php

            include_once('resource/buildtalentpage.php');

            while($row = mysqli_fetch_array($result2)) {
            echo getTalentDetails($row);
            }   

            ?>




///////////   Loads of HTML   ///////////




            <?php

            include_once('resource/buildtalentpage.php');

            while($row = mysqli_fetch_array($result2)) {
            echo getTalent($row);
            }   

            ?>

The good news is, I don't get the error any more. The bad news is, that function 'getTalent' no longer seems to be called?

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2条回答 默认 最新

  • douyan3478 2013-09-25 15:29
    关注

    The result set from mysql doesn't get reset so your second loop condition returns false the first time through, hence the code never gets called. The easiest thing to do here is do all of your work in one loop.

    <?php
    
        include_once('resource/buildtalentpage.php');
        $talentHtml = "";
        while($row = mysqli_fetch_array($result2)) {
            echo getTalentDetails($row);
            $talentHtml.= getTalent($row);
        }   
    
        ?>
    
    ///////////   Loads of HTML   ///////////
    
    <?php
        echo $talentHtml;
    
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