I am fetching rows from a mysql table (jobs). Inside of that fetch, I am also fetching from another table (accounts) [to receive account api keys all depending on what ID_ASSOC is attacted to the job]: below is the code
$sql = "SELECT * FROM jobs";
$query = mysqli_query($db_conx, $sql);
while($row = mysqli_fetch_assoc($query)){
echo $row['action'];
echo "<br/>";
$job_poster_id = $row['id_assoc'];
$sql = "SELECT * FROM accounts WHERE id_assoc='$job_poster_id'";
$query = mysqli_query($db_conx, $sql);
while($rows = mysqli_fetch_assoc($query)){
$username = $rows['twitter_username'];
$consumer_key = $rows['consumer_key'];
$consumer_secret = $rows['consumer_secret'];
$access_token = $rows['access_token'];
$access_token_secret = $rows['access_token_secret'];
}
echo $job_poster_id ;
echo "<br/>";
echo $twitter_username;
echo "<br/>";
echo "----------------------------------";
echo "<br/>";
}
OUTPUT:
specific-message
4
admin
----------------------------------
When I do this, I only get one row output..and I can't seem to find out why. I want the above out put to repeat as many times as it has rows, and it's only doing one row (with the account fetch in the code). However when I do it without the internal fetch (accounts fetch), it returns multiple rows just as desired. Why is this? (below is sample code WITHOUT the accounts fetch):
$sql = "SELECT * FROM jobs";
$query = mysqli_query($db_conx, $sql);
while($row = mysqli_fetch_assoc($query)){
echo $row['action'];
echo "<br/>";
$job_poster_id = $row['id_assoc'];
echo $job_poster_id ;
echo "<br/>";
echo "----------------------------------";
echo "<br/>";
}
OUTPUT:
specific-message
4
----------------------------------
specific-message
1
----------------------------------
specific-message
2
----------------------------------