无法使用类中定义的变量

Question

Hi i am trying to import the configuration variables from a config file that i had created

Config.php has

class Config
{
    public $SERVERNAME = '*******';
    public $SUSERNAME = '*********';
    public $SPASSWORD = '*********';
    public $DBNAME2 = '********';
}

for importing this variable in another file i tried

include('./Config.php') or die("error");
$cnfig = new Config();

But when i try to use $cnfig->DBNAME2 its not working

Please help to sole this problem.

Thank you.

EDIT

It was working in localsystem , when i tied to upload through web hosting it was not working.

Answer 1

Try below one

include  ('./Config.php');
$cnfig = new Config();
echo "<pre>";print_r($cnfig);

Edit:

I am getting below output so it should be working for you too.

Config Object
(
    [SERVERNAME] => *******
    [SUSERNAME] => *********
    [SPASSWORD] => *********
    [DBNAME2] => ********
)

Edit:2

You can also do like this

(include('./Config.php')) or die("error");
$cnfig = new Config();
echo "<pre>";print_r($cnfig);

http://www.php.net/manual/en/function.include.php#39043

or has higher priority than include()

Error Ouput:

When only use include('./Config.php') or die("error"); it's giving below error.

---

Warning: include(1) [function.include]: failed to open stream: No such file or directory in D:\path_to_file\myConfig.php on line 2

Warning: include() [function.include]: Failed opening '1' for inclusion (include_path='.;D:\ZendServer\share\ZendFramework\library') in D:\path_to_file\myConfig.php on line 2

Fatal error: Class 'Config' not found in D:\path_to_file\myConfig.php on line 6