删除PHP中的圆括号之间的所有内容？

Question

I want to remove round brackets and anything between them. Which RE i used ? I used below code but some some language like Hindi it's not work some time. Please any one help me.

nl2br(preg_replace("/\([^)]+\)/","",$main_ary[$y]." "));
//Ex. एंड्रॉयड 4.4.2 (किटकैट) ऑपरेटिंग सिस्टम पर
//I want एंड्रॉयड 4.4.2 ऑपरेटिंग सिस्टम पर

Answer 1

You can use lazy selection (.*?) to skip all sorts of characters until the first occurrence of the next character in the regular expression ()) is reached.

preg_replace("/\(.*?\)/","",$main_ary[$y]." ")