dqjo4340
2014-06-04 18:38
浏览 36
已采纳

如何从父抽象类访问类属性到静态方法?

Here is a simple example.

abstract class A{
  protected $foo = 'I m foo'; 
}

class B extends A{
  static function sayFoo(){
     // get the value of $foo here. 
  }
}

I can pass foo as a constant, or change the function from static to normal, or declare sayFoo inside the parent class but I want to check if there is another way first without using Reflection

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这是一个简单的例子。

 抽象类A {
 protected $ foo ='I m foo';  
} 
 
class B扩展了A {
静态函数sayFoo(){
 //在这里获取$ foo的值。  
} 
} 
   
 
 

我可以将foo作为常量传递,或者将函数从static更改为normal,或者声明 sayFoo 在父类中,但我想在不使用Reflection 的情况下检查是否有另一种方法

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1条回答 默认 最新

  • drpfu51608120170 2014-06-04 18:46
    已采纳

    You can't access the protected $foo property statically because it isn't declared static. However you could if it was an object. One way to go about this is instantiate the class inside of your static function.

    <?php
    
    abstract class A{
      protected $foo = 'I m foo'; 
    }
    
    class B extends A{
      static function sayFoo(){
         // get the value of $foo here. 
          $bar = new self();
          echo $bar->foo;
      }
    }   
    
    B::sayFoo(); //prints 'I m foo';
    
    ?>
    
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