Symfony - 如何在控制器中生成带参数的url

Question

I want to generate a url like ../profile/firstname.lastname

But i don't understand how i can do this because i want in my php also the id from the user.

this is my controller:

       $controllers
            ->match('profile/{firstname.lastname}/', array($this, 'profile'))
            ->assert('userId', '\d+')
            ->method('GET|POST')
            ->before(array($this, 'checkLogin'))
            ->bind('home.profile');

Answer 1

You have to build your Route like this

<route id="profile" path="/profile/{first_name}.{last_name}">
        <default key="_controller">...</default>
    </route>

And in controller create like this

$this->generateUrl('profile', [ 'first_name' => 'skowron', 'last_name' => 'line' ]);

but if you have 2 profiles with this same data it will give you bad results. Then you can create slug or add id parameter to your route