提交内部循环多个ID的按钮？（购物车）

Question

I want to Create a Shoping Cart on PHp,

The Code is simple, When the customer fill the QTY and click button Add to cart, the code will save the PRoduct ID and Qty to a Cart Table. But the problem is that Form inside the Looping. And How Can I Get ID and Qty only from The button that Customer Click.

The Program look like this

And The Script Like This

<?php

    if(isset($_POST[ADD]))
        {
            $qty   = $_POST[QTY];
            $harga = $_POST[HARGA_ASLI]; 
            $id    = $_POST[ID];

            print_r($_POST);
        }

         $kolom = 3;

        $sql = "SELECT *,FORMAT(harga,0)AS harga_digit FROM item";

        $hasil = mysql_query($sql);
        echo "<form method=POST action=index.php>";
        echo "<table>
               <tr>";
              $i = 0;
              while($data=mysql_fetch_array($hasil))
              {
                 if($i >= $kolom)
                 {
                    echo "</tr><tr>";
                    $i = 0;
                 }          
                 $i++;
                 echo "<td align='center'><br><a href='detailBarang.php?ID=$data[ID]'><img src='$data[img]' width='200' height='150'/><br>$data[nama_produk]</a><br>
                         Rp. $data[harga_digit]<br> 
                         <input type='submit' name='ADD' id='ADD' value='Add to Cart'>
                         <input type='text' name='QTY' id='QTY' placeholder='Qty' /><br>
                         <input type='hidden' name='HARGA_ASLI' id='HARGA_ASLI' value='$data[harga]' /><br>
                         <input type='hidden' name='ID' id='ID' value='$data[ID]' />
                         <br></td>";


              }//end of while

        echo "<tr></table>";
        echo "</form>"; 

  ?>

If i fill the Qty and click Add to Cart, only the last Item can Post The Data.

How To Post The data Only for Customer Choose?

Im very Appreciated Your Answer.

Thanks

Answer 1

First, let's convert your MySQL to MySQLi. More explanation inside the comments /* */:

<?php   
        $connection=mysqli_connect("YourHost","YourUsername","YourPassword","NameofYourDatabase");

if(mysqli_connect_errno()){

echo "Error".mysqli_connect_error();

}

$res=mysqli_query($con,"SELECT * FROM item");

while($row=mysqli_fetch_array($res)){

$nameofsubmitbutton=$row['ID'];

if(isset($_POST[$nameofsubmitbutton])){

$nameofproduct=$row['namaproduk'];
$nameofnumbersubmitted=$nameofsubmitbutton."number";
$quantity=$_POST[$nameofnumbersubmitted];

if(empty($quantity)){
echo "You wanted to buy a ".$nameofproduct."?<br>Type in a number so you can add it to your cart.";
}

else {
mysqli_query($connection,"INSERT INTO yourTable ('','') VALUES ('$quantity','$nameofproduct')");
echo "You bought ".$quantity." of ".$nameofproduct;
}

} /* END OF IF ISSET */

} /* END OF WHILE LOOP $RES */

$kolom = 3;

$hasil = mysqli_query($connection,"SELECT *,FORMAT(harga,0) AS harga_digit FROM item"); /* YOU SURE WITH THIS QUERY? */

echo "<form method=POST action=''>"; /* SUBMIT ON ITSELF */
echo "<table><tr>";

$i = 0; /* THIS WOULD ALSO SET AS YOUR COUNTER */
while($data=mysqli_fetch_array($hasil))
{

$id=$data['ID'];

if($i >= $kolom){

echo "</tr><tr>";
$i = 0;

} /* END OF IF $i >= $KOLOM */   

$i++;

echo "<td align='center'><br><a href='detailBarang.php?ID=$data[ID]'><img src='$data[img]' width='200' height='150'/><br>".$data[nama_produk]."</a><br>Rp. ".$data[harga_digit]."<br>"; /* IF TO ECHO VARIABLES, USE ".$variable." */

$numbername=$id."number";

echo "<input type='number' name='$numbername' id='QTY' placeholder='Qty' /><br>"; /* CHANGE YOUR INPUT TYPE TO NUMBER */

/* NO NEED FOR THE HIDDEN INPUT */

echo "<input type='submit' name='$id' id='ADD' value='Add to Cart'></td>"; /* CHANGE THE NAME OF SUBMIT BUTTON TO THE CORRESPONDING ID FROM YOUR TABLE */



} /* END OF WHILE LOOP */

echo "<tr></table>";
echo "</form>"; 

?>

I tried it on my local computer. You should too.

Here's a sample screen shot.