I'm trying to make a form for the user to upload multiple images at a time. I am trying to make all of the images that are submitted at once to be put into the same MySQL table row. The issue I am having is that when the user submits an image(s), all data is submitted properly into the columns, except for the image, image1, image2, image3, and image4 columns. These columns are the ones that hold the actual image file, i presume. For example, I submitted an image, and the image column shows [BLOB - 14 B], when I believe it should be at least 300 KB. I also have a viewimage.php page that should normally display an image, and it is showing a tiny error picture. I believe that means the column does not contain any image file.
Here is my full PHP page code:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
<head><title>File Upload To Database</title></head>
<body>
<h2>Please Choose a File and click Submit</h2>
<form enctype="multipart/form-data" action="<?php echo htmlentities($_SERVER['PHP_SELF']);?>" method="post">
<input type="hidden" name="MAX_FILE_SIZE" value="99999999" />
<div><input name="userfile[]" type="file" /></div>
<div><input name="userfile[]" type="file" /></div>
<div><input name="userfile[]" type="file" /></div>
<div><input name="userfile[]" type="file" /></div>
<div><input name="userfile[]" type="file" /></div>
<div><input type="submit" value="Submit" /></div>
</form>
</body></html>
<?php
/*** check if a file was submitted ***/
if(!isset($_FILES['userfile']))
{
echo '<p>Please upload a display picture.</p>';
}
else
{
try {
upload();
/*** give praise and thanks to the php gods ***/
echo '<p>Thank you for submitting</p>';
}
catch(Exception $e)
{
echo '<h4>'.$e->getMessage().'</h4>';
}
}
/*
* Check the file is of an allowed type
* Check if the uploaded file is no bigger thant the maximum allowed size
* connect to the database
* Insert the data
*/
/**
*
* the upload function
*
* @access public
*
* @return void
*
*/
function upload(){
$maxsize = 99999999;
$columnNames = '';
$columnValues = '';
$paramsToBeBound = array();
echo '<pre>' . print_r($_FILES, TRUE) . '</pre>';
/*** check if a file was uploaded ***/
for($i = 0; ($i < count($_FILES['userfile']['tmp_name']) && $i < 5); $i++) {
if($_FILES['userfile']['tmp_name'][$i] != '') { // check if file has been set to upload
if($_FILES['userfile']['error'][$i] == 0 && is_uploaded_file($_FILES['userfile']['tmp_name'][$i]) && getimagesize($_FILES['userfile']['tmp_name'][$i]) != false) {
/*** get the image info. ***/
$size = getimagesize($_FILES['userfile']['tmp_name'][$i]);
/*** assign our variables ***/
$type = $size['mime'];
$imgfp = fopen($_FILES['userfile']['tmp_name'][$i], 'rb');
$size = $size[3];
$name = $_FILES['userfile']['name'][$i];
/*** check the file is less than the maximum file size ***/
if($_FILES['userfile']['size'][$i] < $maxsize)
{
if($i > 0) {
$columnNames .= ', image_type' . $i . ', image' . $i . ', image_size' . $i . ', image_name' .$i;
$columnValues .= ', ?, ?, ?, ?';
} else {
$columnNames .= 'image_type, image, image_size, image_name';
$columnValues .= '?, ?, ?, ?';
}
$paramsToBeBound[] = $type;
$paramsToBeBound[] = $imgfp;
$paramsToBeBound[] = $size;
$paramsToBeBound[] = $name;
} else
throw new Exception("File Size Error"); //throw an exception is image is not of type
}
else
{
// if the file is not less than the maximum allowed, print an error
throw new Exception("Unsupported Image Format of image!");
}
}
}
if(count($paramsToBeBound) > 0) {
$dbh = new PDO("mysql:host=scom;dbname=ksm", 'kesgbm', 'Kszer'); // I tested with MySQL database and worked fine.
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $dbh->prepare('INSERT INTO testblob (' . $columnNames . ') VALUES (' . $columnValues . ')');
$i = 0;
foreach($paramsToBeBound as &$param) {
$i++;
if($i == 2 || $i - floor($i / 4) == 2) {
$stmt->bindParam($i, $param, PDO::PARAM_LOB);
} else {
$stmt->bindParam($i, $param);
}
}
$stmt->execute();
}
}
?>
Here is the code I used in PHP MyAdmin SQL to create the MySQL Table:
CREATE TABLE testblob (
image_id tinyint(3) NOT NULL AUTO_INCREMENT,
image_type varchar(25) NOT NULL,
image longblob NOT NULL,
image_size varchar(25) NOT NULL,
image_name varchar(50) NOT NULL,
image_type1 varchar(25) NOT NULL,
image1 longblob NOT NULL,
image_size1 varchar(25) NOT NULL,
image_name1 varchar(50) NOT NULL,
image_type2 varchar(25) NOT NULL,
image2 longblob NOT NULL,
image_size2 varchar(25) NOT NULL,
image_name2 varchar(50) NOT NULL,
image_type3 varchar(25) NOT NULL,
image3 longblob NOT NULL,
image_size3 varchar(25) NOT NULL,
image_name3 varchar(50) NOT NULL,
image_type4 varchar(25) NOT NULL,
image4 longblob NOT NULL,
image_size4 varchar(25) NOT NULL,
image_name4 varchar(50) NOT NULL,
image_ctgy varchar(25) NOT NULL,
KEY image_id (image_id)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
Thank you for any help. I appreciate all help given.
Additional Information: The form is only supposed to submit images if at least the first input has been given an image. If the user leaves the first image input blank but chooses the second to input an image, the form won't submit. The first image input is supposed to act as the display picture for the user, which is why I would like it to be required, first and foremost. The user shouldn't have to upload all 5 images for the form to submit.
