.serialize不能正确传递参数

Question

I am sending a serialized form with $.post to a Controller PHP:

$.post('/Controller.php',
    {
        action: 'register',
      data: $('#regForm').serialize()                       
    },
  function(msg){

        if(parseInt(msg.status)==1)
        {
            window.location=msg.txt;
        }
        else if(parseInt(msg.status)==0)
        {
            error(1,msg.txt);
        }

        hideshow('loading',0);
    }, 
    "json"      
);  

I would now expect to be able to access the Form fields by $_POST['fieldname'] but INSTEAD I have a Get like parameter string in $_POST['data'] -.- What do I do wrong ?

Answer 1

It's sending the data just as you told it to. .serialize() creates a "query string", which you added into $_POST['data'].

Instead of what you have, try this:

var formData = $('#regForm').serialize();
var extraFields = {action: 'register'};

$.post('/Controller.php', $.param(extraFields)+'&'+formData, function(msg){
    if(parseInt(msg.status)==1)
    {
        window.location=msg.txt;
    }
    else if(parseInt(msg.status)==0)
    {
        error(1,msg.txt);
    }

    hideshow('loading',0);
}, 'json');

Now you should be able to get $_POST['action'] and $_POST['fieldname'].