I am trying to make a validation for login form. What I am doing is to check in database for username and password and if that user doesn't exists to show a message, if it exists redirect to index.php. I have done this using Ajax but the problem is that it shows me the message of failure, but when try to login as an existing user it shows this error at inspect element
Uncaught TypeError: Cannot call method 'append' of null jquery-1.9.1.js:7985
and
Uncaught TypeError: Cannot read property 'settings' of undefined jquery.validate.js:332
script.js :
$('#login_form').on('submit', function(e) {
e.preventDefault();
var username = $('#login_form input[name=username]').val();
var password = $('#login_form input[name=password]').val();
$.ajax({
url: "login.php",
type: "POST",
data: {username: username,
password: password},
success: function(response) {
$('#invalid_content').html(response);
}
});
});
login_form.php
<form id="login_form" action="login.php" method="post">
<div id="invalid_content" style="color: red"></div><br>
<div class="control-group">
<input autofocus id="username" name="username" placeholder="Username" type="text"/>
</div><br>
<div class="control-group">
<input id ="password" name="password" placeholder="Fjalekalimi" type="password"/>
</div><br>
<div class="control-group">
<button type="submit" class="btn">Log In</button>
</div>
<br>
</form>
login.php
if ($_SERVER["REQUEST_METHOD"] == "POST")
{
$rows = query("SELECT * FROM users WHERE username = ?", $_POST["username"]);
if (count($rows) == 1)
{
$row = $rows[0];
if (crypt($_POST["password"], $row["hash"]) == $row["hash"])
{
$_SESSION["id"] = $row["id"];
echo json_encode(array('msg'=>"Success.", 'url'=>"/kinema/html/index.php", 'status'=>true));
}
}
else if (($_POST["password"], $_POST["username"]) == null){
echo json_encode(array('msg'=>"Username ose fjalekalimi jane te pavlefshem.", 'url'=>"", 'status'=>false));
}
}
else
{
echo json_encode(array('msg'=>"Username ose fjalekalimi jane te pavlefshem.", 'url'=>"", 'status'=>false));
}
The respone form console is:
<br />
<font size='1'><table class='xdebug-error xe-parse-error' dir='ltr' border='1' cellspacing='0' cellpadding='1'>
<tr><th align='left' bgcolor='#f57900' colspan="5"><span style='background-color: #cc0000; color: #fce94f; font-size: x-large;'>( ! )</span> Parse error: syntax error, unexpected ',' in C:\wamp\www\kinema\html\login.php on line <i>23</i></th></tr>
</table></font>