douyin4875 2013-12-11 10:30
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单击按钮时用户输入的POST查询

This is what I'm trying to do. I let the user to input DATEFROM and DATETO. Then when the user click the button, it will execute a query to SELECT * from my table WHERE DATEFROM BETWEEN DATETO. I don't know what's wrong. Please help.

<html>
    <head></head>
    <body>
        <?php
        <form method="POST" action="">
        DATE FROM: <input type="date" name="datefrom"> TO: <input type="date" name="dateto"> <input type="submit" value="Extract excel file" name="extract"></input>
        </form>

        $datefrom = "datefrom";
        $dateto = "dateto";

        if(isset($_POST['extract'])){
            mysql_connect("localhost", "root");
            mysql_select_db("sample");

            $myquery = "SELECT * FROM biometrics WHERE date_created BETWEEN '" . $datefrom . "' AND '" . $dateto . "ORDER BY id_biometrics";


            $result = mysql_query($myquery);

            echo "<table border='1'>
            <tr>
                <th>ID</th>
                <th>Employee Number</th>
                <th>Date Created</th>
                <th>Time Created</th>
                <th>Status</th>
            </tr>";

            while($data = mysql_fetch_row($result))
            {
                echo("<tr>
                <td>$data[0]</td>
                <td>$data[1]</td>
                <td>$data[2]</td>
                <td>$data[3]</td>
                <td>$data[4]</td>
                </tr>");
            }

            echo "</table>";

        }

        ?>
    </body>
</html>
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4条回答 默认 最新

  • duanpu1111 2013-12-11 10:37
    关注

    you have missed a quote(') in query ,try like this

    if(isset($_POST['extract'])){
            mysql_connect("localhost", "root");
            mysql_select_db("sample");
    
              $datefrom = $_POST['datefrom'];
              $dateto = $_POST['dateto'];
    
            $myquery = "SELECT * FROM biometrics WHERE date_created BETWEEN '" . $datefrom . "' AND '" . $dateto . "' ORDER BY id_biometrics";
    
    
            $result = mysql_query($myquery);
    

    hope this works for you

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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