donglu7286 2013-08-13 17:30
浏览 30

将JSON发送到PHP并获得响应

I'm just learning how to use jQuery and PHP together. This is my first attempt, and I feel like I'm almost getting the concept. However, there's an issue I failed to address. When I post a JSON object to PHP script and try to return one of the parameters, I get the following error : "Trying to get property of non-object in ..."

index.html:

<!DOCTYPE html>
<html>
    <head>
        <script src="http://code.jquery.com/jquery-git2.js"></script>
        <meta charset=utf-8 />
        <title>JS Bin</title>
        <style id="jsbin-css"></style>
    </head>
    <body>
        <button onClick="postData();">Submit me!</button>
        <script>
            function postData() {
                var myData = {
                    'firstName' : 'John',
                    'lastName' : 'Doe'
                };   

                $.ajax( {
                    type: "POST",
                    url: "postData.php",
                    contentType: "application/json",
                    data: myData,
                    success: function(msg){ 
                        alert(msg);
                    },
                    error: function(err) {
                         alert('error!' + err);
                    }
                });
            }
        </script>
    </body>
</html>

postData.php:

<?php
    $input = file_get_contents('php://input');
    $jsonData = json_decode($input);    
    $output = $jsonData->{'firstName'};
    echo $output;
?>
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4条回答 默认 最新

  • douzhan3900 2013-08-13 17:34
    关注

    json_decode (depending on PHP version) defaults to returning an array, not an object. The proper way to access it would be:

    $output = $jsonData['firstname'];

    You'll also want it to return an associative array, so pass true as the second argument of json_decode.

    $jsonData = json_decode($input, true);

    What could alternately be happening is that the JSON is invalid, in which case PHP returns null. You can check for that:

    if ($jsonData = json_decode($input, true) === null) {
    // Do stuff!
} else {
    // Invalid JSON :(
}
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