douxiaochun4964 2013-07-24 16:08
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PHP将空月插入foreach循环

I have am using MySQL to generate data for a graph. The graph needs to include the months that have past during the current year. For Example: Today is July so the graph should include January-July. The SQL data does not have numbers for each month.

Here is my SQL Output:

Units_Counted           Date 
    607                   2
    2120                  5
    42                    7

The "date" field is the month. When I print it to the graph I need it to look like this.

Units_Counted           Date
    0                     1
    607                   2
    0                     3
    0                     4
    2120                  5
    0                     6
    42                    7

Here is my current PHP code. I need to add another loop in here but I cant seem to get it right.

$Month = 1;
foreach ($stmtIndividualGraphDatarows as $stmtIndividualGraphDatarow){
    if ($stmtIndividualGraphDatarow['GraphMonth'] == $Month)
        {
        echo "{";
            echo "'x': '".$stmtIndividualGraphDatarow['GraphMonth']."',";
            echo "'y':".$stmtIndividualGraphDatarow['GraphCounts'];
        echo "},";
        }
    else {
        echo "{";
            echo "'x': '".$Month."',";
            echo "'y': 0";
        echo "},";}
        $Month++;
        }
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1条回答 默认 最新

  • drjk87189 2013-07-24 16:28
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    Hope my code will be helpful:

     <?php
     $list = array(
         array(
             'GraphMonth' => 2,
             'GraphCounts' => 607,
         ),
         array(
             'GraphMonth' => 5,
             'GraphCounts' => 2120,
         ),
         array(
             'GraphMonth' => 7,
             'GraphCounts' => 42,
         ),
     );
     $max = 0;
    
     $month_count = array();
     foreach ($list as $item)
     {
         $month = $item['GraphMonth'];
         $count = $item['GraphCounts'];
         if ($month > $max)
         {
             $max = $month;
         }
         $month_count[$month] = $count;
     }
    
     for ($i = 1; $i <= $max; $i++)
     {
         $month = $i;
         $count = 0;
         if (isset($month_count[$i]))
         {
             $count = $month_count[$i];
         }
         $msg = "{'x': '$month', 'y': '$count'}";
         echo $msg, "
    ";
     }
     // output:
     //{'x': '1', 'y': '0'}
     //{'x': '2', 'y': '607'}
     //{'x': '3', 'y': '0'}
     //{'x': '4', 'y': '0'}
     //{'x': '5', 'y': '2120'}
     //{'x': '6', 'y': '0'}
     //{'x': '7', 'y': '42'}
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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