PHP json_encode结果和jQuery

Question

I'm trying to take a jSON encoded string out of my database and loop through the items but I'm having some difficulty. Here's the string in the database:

["volunteers","seat_dedication_program","memberships"]

And here is the code:

//Looks for _checkbox when looping through my database fields (object dbVals) and turns it into a true jQuery array if it finds it.
if( key.search(/_checkbox/i) > 0 ) var arr = $.makeArray(dbVals[key]);

//If it is an array, loop through the array values and show them
if($.isArray(arr)==true){
    $.each(arr, function(i, n){
        alert(i + " : " + n);
    });
}

What I want is this:

//alert
0 : volunteers
//alert
1 : seat_dedication_program etc...

What I'm getting is this:

//alert
0 : ["volunteers","seat_dedication_program","memberships"]

I think I've included all relevant data. Can anyone help me figure out why this is happening?

Thanks.

Answer 1

Using $.makeArray(..) is giving you an array where the only element is the string you gave it. You need to parse the string into a JavaScript object. Use the JSON2.js library to parse then your code would look something like this.

var arr = JSON.parse(dbVals[key]);

if($.isArray(arr)==true){
    $.each(arr, function(i, n){
        alert(i + " : " + n);
    });
}