解析错误：语法错误，第25行的C：\ xampp \ htdocs \ tlsproject \ server.php中的意外'}'重复]

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• PHP parse/syntax errors; and how to solve them? 17 answers

Parse error: syntax error, unexpected '}' in C:\xampp\htdocs\tlsproject\server.php on line 25

looked over and over but still couldnt find the error

<?php

  session_start();

  //initializare variabile

  $username = "";
  $email = "";

  $errors = array();

  //conectare la baza de datefmt_create

  $db = mysqli_connect('localhost','root','','project') or die("Could not connect to database");

  //Inregistrare user

  $username = mysqli_real_escape_string($db, $_POST['username']);
  $email = mysqli_real_escape_string($db, $_POST['email']);
  $password_1 = mysqli_real_escape_string($db, $_POST['password_1']);
  $password_2 = mysqli_real_escape_string($db, $_POST['password_2']);

  //Validare

  if(empty($username)) {array_push($errors, "Username is required")};
  if(empty($email)) {array_push($errors, "Email is required")};
  if(empty($password_1)) {array_push($errors, "Password is required")};
  if($password_1 != $password_2) {array_push($errors, "Passwords do not match")};

  //Unicitate username

  $user_check_query = "SELECT * FROM user WHERE username = '$username' or email = '$email' LIMIT 1";

  $results = mysqli_query($db, $user_check_query);
  $user = mysqli_fetch_assoc($result);

  if($user)
  {
    if($user['username'] === $username){array_push($errors, "Username already exists");}
    if($user['email'] === $email){array_push($errors, "This email is already being used");}
  }

  //Inregistrare user

  if(count($errors) == 0){

    $password = md5(password_1); // encriptare parola
    $query = "INSERT INTO user (username, email, password) VALUES ('$username', '$email', '$password')";
    mysqli_query($db,$query);
    $_SESSION['username'] = $username;
    $_SESSION['success'] = "You are now logged in";

    header('location: index.php');
  }

 ?>

Parse error: syntax error, unexpected '}' in C:\xampp\htdocs\tlsproject\server.php on line 25

</div>

Answer 1

error is here brother, semicolon(;) after braces...

if(empty($username)) {array_push($errors, "Username is required")};
if(empty($email)) {array_push($errors, "Email is required")};
if(empty($password_1)) {array_push($errors, "Password is required")};
if($password_1 != $password_2) {array_push($errors, "Passwords do not match")};

change it to this

if(empty($username)) {array_push($errors, "Username is required");}
  if(empty($email)) {array_push($errors, "Email is required");}
  if(empty($password_1)) {array_push($errors, "Password is required");}
  if($password_1 != $password_2) {array_push($errors, "Passwords do not match");}