功能 - 删除3个持续元素[重复]

Question

This question already has an answer here:

• What's the most efficient way to array_pop() the last n elements in an array? 4 answers

Function don't work

$k = array('one','two','three','four','five','six','seven','eigth','nine');


    function del_el_3($array){
        for($i = 0; $i < 3; $i++){
            unset($array[array_pop($array)]);
        }
    }


    del_el_3($k);


    echo "<pre>";
    var_dump($k);
    echo "</pre>";

</div>

Answer 1

You are not using $i inside the for loop to get the index of the value

Also, you are unsetting as well as popping, both do the same sort of thing.

So you should only need to do this:

function del_el_3($array){
    for($i = 0; $i < 3; $i++){
        unset($array[$i]);
    }
}

Or this:

function del_el_3($array){
    for($i = 0; $i < 3; $i++){
        array_pop($array);
        print_r($a);
    }
}

Which will remove the 3 elements, and you can also print them if you so desire.