dousi4257 2019-05-02 10:26
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如何在Wordpress函数中简化此代码?

I'm Trying to make a function, my code works but i wonder is there any way to simplify my code? with loop maybe?

Background:

I try to show data from usermeta (the usermeta from plugin) so these are the meta key:

  • child_name
  • child_name_1
  • child_name_2
  • child_name_3

and so on.. based on how much user input their children in database.

example, if user only input 2 children, meta key will be:

  • child_name
  • child_name_1

temporary, i limit only 3 children to input, because i can't simplify it.

function get_child_name(){

$user = wp_get_current_user();
$count_extra_field = $user->wppb_repeater_field_15_extra_groups_count;
$count_child = $count_extra_field + 1;


$child_name_0 = $user->child_name;
$child_name_1 = $user->child_name_1;
$child_name_2 = $user->child_name_2;

$child_names = array($child_name_0,$child_name_1,$child_name_2);

$n=0;
foreach($child_names as $child_name) {
if($n==$count_child) break;
$n++;
echo $child_name;
}
}
add_shortcode('child_names', 'get_child_name');

Above code is works, as I use it now. but is it possible to simplify it / automate the process? So, user can input as many children as possible. or if I want to increase the limit (for input children names) I don't have to add the code again manually, is it possible?

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1条回答 默认 最新

  • dongting3135 2019-05-03 08:46
    关注

    I have tried to simplify the code. Meta fields are being created dynamically based on index. Please check code below. With this you dont have to touch this function again when you want to increase the number of fields.

    function get_child_name(){
    
        $user = wp_get_current_user();
    
        $count_extra_field = $user->wppb_repeater_field_15_extra_groups_count;
    
        $names = array();
    
        for ( $i = 0; $i < $count_extra_field; $i++ ) {
            $meta_key = 'child_name';
            $key_suffix = ( 0 === $i ) ? '' : '_' . $i ;
            $meta_key .= $key_suffix;
    
            if ( $user->$meta_key ) {
                $names[] = $user->$meta_key;
            }
        }
    
        if ( ! empty( $names ) ) {
            foreach ( $names as $name ) {
                echo $name;
            }
        }
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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