dongli1920 2019-03-30 08:24
浏览 79
已采纳

如何使用ajax从数据库中获取下一行/上一行

I am trying to fetch next previous rows from mysql database to ajax

I managed to do it but i have a problem when i click previous button it always send me back to the first result

<script>
    $(document).ready(function(){
        var card_id = document.getElementById('cardid').value
        $(document).on('click', '#previous', function(){
            $.ajax({
                url:"includes/fetchcards.php",
                method:"POST",
                dataType: 'json',
                data:{card_id:card_id,prev:1},
                success:function(data)
                {

                    $('#cardfront').text(data.front)
                    $('#cardback').text(data.back);
                    card_id = data.id
                    alert(card_id)



                }
            });
        });

        $(document).on('click', '#next', function(){
            $.ajax({
                url:"includes/fetchcards.php",
                method:"POST",
                dataType: 'json',
                data:{card_id:card_id, next:1},
                success:function(data)
                {
                    $('#cardfront').html(data.front)
                    $('#cardback').html(data.back);
                    card_id = data.id
                    alert(card_id)



                }
            });
        });

    });
</script>

php code

<?php
include 'config.php';
if(isset($_POST["card_id"]))
{
    $card_id = $_POST["card_id"];
    if(isset($_POST["next"])){
        $db->where("id", $card_id,  ">") ;
        $flaschcard = $db->getOne('cards') ;
    }
    if(isset($_POST["prev"])){
        $db->where("id", $card_id,  "<") ;
        $flaschcard = $db->getOne('cards') ;
    }
    if(isset($flaschcard)) {
        echo json_encode($flaschcard);
    }
}


I expect that when i click previous button it shows the previous row but it always send me back to the first result

  • 写回答

1条回答 默认 最新

  • dqmg80654 2019-03-30 08:39
    关注
    if(isset($_POST["prev"])){
        $db->where("id", $card_id,  "<") ;
        $db->orderBy("id", "desc"); // Reverse the order to fetch the last one
        $flaschcard = $db->getOne('cards') ;
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 MapReduce结果输出到HBase,一直连接不上MySQL
  • ¥15 扩散模型sd.webui使用时报错“Nonetype”
  • ¥15 stm32流水灯+呼吸灯+外部中断按键
  • ¥15 将二维数组,按照假设的规定,如0/1/0 == "4",把对应列位置写成一个字符并打印输出该字符
  • ¥15 NX MCD仿真与博途通讯不了啥情况
  • ¥15 win11家庭中文版安装docker遇到Hyper-V启用失败解决办法整理
  • ¥15 gradio的web端页面格式不对的问题
  • ¥15 求大家看看Nonce如何配置
  • ¥15 Matlab怎么求解含参的二重积分?
  • ¥15 苹果手机突然连不上wifi了?