dongyounai6281 2018-10-22 11:55
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PHP仅上传文件图像

I am not able upload my image file to server, using XAMMP phpmyadmin and apache services. I'm wondering where I did wrong.
I have to use this kind of security code to prevent any extension upload that can exploit by hacker.
It just shows that the files is "Your image was not uploaded" as an error code. Not sure if it is because I didn't specify the root of the website? If yes, how can I specify?

<html>
<head> 
<?php
if(isset($_POST['submit']))
{
$target_dir = '/uploads/';
$target_dir1 = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadedname=$_FILES['fileToUpload']['name'];
$uploadedname_temp=$_FILES['fileToUpload']['name'];
$uploaded_ext=substr($uploadedname_temp,strrpos($uploadedname_temp,'.')+1);
$uploaded_size=$_FILES['fileToUpload']['size'];
if(isset($_POST['submit']))
{
if (($uploaded_ext == "jpg" || $uploaded_ext == "JPG" || $uploaded_ext == "jpeg" || $uploaded_ext == "JPEG") && ($uploaded_size < 1000000)){ 
                if(!move_uploaded_file($_FILES['fileToUpload']['name'], $target_dir1)) { 

                    echo '<pre>'; 
                    echo 'Your image was not uploaded.'; 
                    echo '</pre>'; 

                  } else { 

                    echo '<pre>'; 
                    echo $target_dir1. ' succesfully uploaded!'; 
                    echo '</pre>'; 

                    } 
            } 

            else{ 

                echo '<pre>'; 
                echo 'Your image was not uploaded.'; 
                echo '</pre>'; 

            }   
}

}

?>



</head>
<body>




<form action="uploadfiles.php" method="post" enctype="multipart/form-data">
    Select image to upload:
    <input type="file" name="fileToUpload" id="fileToUpload">
    <input type="submit" value="Upload Image" name="submit">
</form>


</body>
</html>
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2条回答 默认 最新

  • doutui8842 2018-10-22 12:29
    关注

    I tried below code. it is working properly. As there was issue with $uploaded_size you have not declared size variable and used that.

        <html>
        <head> 
    
        <?php
        if(isset($_POST['submit']))
        {
        $target_dir = realpath(__DIR__) . '/uploads/';
        $target_dir1 = $target_dir . basename($_FILES["fileToUpload"]["name"]);
        $uploadedname=$_FILES['fileToUpload']['name'];
        $uploadedname_temp=$_FILES['fileToUpload']['name'];
        $uploaded_size = $_FILES['fileToUpload']['size'];
        $uploaded_ext=substr($uploadedname_temp,strrpos($uploadedname_temp,'.')+1);
    
        if(isset($_POST['submit']))
            {
             if (($uploaded_ext == "jpg" || $uploaded_ext == "JPG" || $uploaded_ext == "jpeg" || $uploaded_ext == "JPEG") && ($uploaded_size < 1000000)){ 
                        if(!move_uploaded_file($_FILES['fileToUpload']['tmp_name'], $target_dir1)) { 
    
                            echo '<pre>'; 
                            echo 'Your image was not uploaded.'; 
                            echo '</pre>'; 
    
                          } else { 
    
                            echo '<pre>'; 
                            echo $target_dir1. ' succesfully uploaded!'; 
                            echo '</pre>'; 
    
                            } 
                    } 
    
                    else{ 
    
                        echo '<pre>'; 
                        echo 'Your image was not uploaded.'; 
                        echo '</pre>'; 
    
                    }   
        }
    
        }
    
        ?>
    
    
    
        </head>
        <body>
    
    
    
    
        <form action="uploadfiles.php" method="post" enctype="multipart/form-data">
            Select image to upload:
            <input type="file" name="fileToUpload" id="fileToUpload">
            <input type="submit" value="Upload Image" name="submit">
        </form>
    
    
        </body>
        </html>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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