从外部URL获取特定内容 - PHP

Question

I am trying to get the direct download link from Google Drive, so I want to get specific content from external url.

Example: visit x link and get the url from this div or from this class! I think that this is possible, but I don't know how to do it.

 $dom = new DOMDocument;
 libxml_use_internal_errors(true);
 $dom->loadHTMLFile('https://drive.google.com/uc?id=12ejMrVziFpjcEpG9A2Ks4yoNDJ9qz0B5&export=download');
 $DOMxpath = new DOMXPath($dom);
 $DivContent = $DOMxpath->query("//div[@id='uc-download-link']");
 $bigDiv = $DivContent;
 $link = $bigDiv->find('a');
 echo $link->href . '<br>';

Is that possible with <kbd>PHP</kbd> or <kbd>JavaScript</kbd>?

Answer 1

Sure, it can be done easily with php's file_get_contents, DOMDocument and DOMXPath.

The following example gets the HREF value from the 'Stack Overflow' logo's <a> tag, which has the class -logo js-gps-track:

$html = file_get_contents('http://stackoverflow.com/');
$dom = new DOMDocument();
libxml_use_internal_errors(true);

$dom->loadHTML($html);
$xpath = new DOMXPath($dom);

// find the element whose href value you want by XPath
$nodes = $xpath->query('//*[@class="-logo js-gps-track"]');

foreach($nodes as $href) {
    // print out the href value
    echo $href->getAttribute( 'href' ); 
}

Obviously you'd just need to amend the URL and the XPath for your specific use case.