donglu1973 2018-12-02 13:12 采纳率: 100%
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是null等于''

I using this code

$dato = array_shift($datos);
while($dato!=''){...}

Is it correct?

Is the same to put:

while($dato!=''){...}

Than

while($dato!=null){...}

Edit: This is on the oficial documentation php

Returns the shifted value, or NULL if array is empty or is not an array.

But my code is actually running

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3条回答 默认 最新

  • dqwh1219 2018-12-02 13:18
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    I think you are trying to check the value is empty in any array

    while(!empty($dato)){...}
    
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