doushi9474 2018-11-22 10:22
浏览 52
已采纳

Wordpress,foreach on taxonomy显示重复

I have the below code, it works initially with regards to the fact that it displays the products for all taxonomies. However if a product is set to 2 taxonomies then it will display twice on the page as opposed to showing the first instance of the product.

<?php if ( $terms && !is_wp_error( $terms ) ) {
    foreach ( $terms as $term ) {

        $args = array(
            'post_type'  => 'products',
            'posts_per_page' => -1,
            'orderby' => 'menu_order',
            'tax_query' => array(
                array(
                    'taxonomy' => 'product_cat',
                    'field'    => 'slug',
                    'terms'    => $term->slug,
                ),
            ),
            'order' => 'asc',
        );

        runQuery($args);
    }
} ?>

Here is the runQuery function:

<?php $x = 0;
function runQuery($args) {
    global $x;
    $query = new WP_Query( $args );

    if ($query->have_posts()) : while ($query->have_posts()) : $query->the_post();
        $cat_terms = get_the_terms($post->id, 'product_cat');
        $datagroups = '';

        foreach ($cat_terms as $key => $cat) {
            if (count($cat_terms) == ($key + 1)) {
                $datagroups .= '"' . $cat->name . '"';
            } else {
                $datagroups .= '"' . $cat->name . '", ';
            }
        }
    ?>      

    HTML Here that is displayed;

    <?php $x ++;
    endwhile;
    endif;
    wp_reset_postdata();
}?>
  • 写回答

1条回答 默认 最新

  • doqau82086 2018-11-22 10:45
    关注

    I have figured this out, I essentially just had to check the current post in the loop to see if it had already been displayed:

    <?php $x = 0;
    $displayed = [];
    
    function runQuery($args) {
        global $displayed;
        global $x;
        $query = new WP_Query( $args );
    
        if ($query->have_posts()) : while ($query->have_posts()) : $query->the_post();
            $cat_terms = get_the_terms($post->id, 'product_cat');
            $datagroups = '';
    
            if ( in_array( get_the_ID(), $displayed ) ){
                continue;
            }
            // update array with currently displayed post ID
            $displayed[] = get_the_ID();
    
            foreach ($cat_terms as $key => $cat) {
                if (count($cat_terms) == ($key + 1)) {
                    $datagroups .= '"' . $cat->name . '"';
                } else {
                    $datagroups .= '"' . $cat->name . '", ';
                }
            }
        ?>  
    

    Source that may help others: https://wordpress.stackexchange.com/questions/285091/avoid-duplicate-post-from-same-taxonomy

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 求差集那个函数有问题,有无佬可以解决
  • ¥15 【提问】基于Invest的水源涵养
  • ¥20 微信网友居然可以通过vx号找到我绑的手机号
  • ¥15 寻一个支付宝扫码远程授权登录的软件助手app
  • ¥15 解riccati方程组
  • ¥15 display:none;样式在嵌套结构中的已设置了display样式的元素上不起作用?
  • ¥15 使用rabbitMQ 消息队列作为url源进行多线程爬取时,总有几个url没有处理的问题。
  • ¥15 Ubuntu在安装序列比对软件STAR时出现报错如何解决
  • ¥50 树莓派安卓APK系统签名
  • ¥65 汇编语言除法溢出问题