douhan5547
2019-03-07 11:53
浏览 66
已采纳

我尝试使用post方法将值从ajax传递给codeigniter控制器,但它返回void

I tried to store ajax value in codeigniter controller variable using post method I used $this->input->post method in the controller but the variable in the controller is not getting the ajax value, the variable is returning as null, help me to find a solution for this error Thanks in advance.

Here is the code:

View:

<button type="button" class="btn btn-info btn-md edit-pdt" data-pid="<?php echo $row->product_id;?>"><i class="fa fa-pencil"></i></button>

Controller:

public function displayprodt()
    {
        $pid= $this->input->get('pid');
        $data = array(
            'title' => "Edit Product",
            'result' => $this->ProductModel->displayprodt($pid)
        );
        $this->load->view('header',$data);
        $this->load->view('navbar');
        $this->load->view('sidebar');
        $this->load->view('editproduct',$data);
        $this->load->view('footer');
    }

JQuery:

$('.edit-pdt').click(function(){
        var base_url = $("#base_url").val();
        var pid = $(this).attr("data-pid");
        alert(pid);
        $.ajax({
           type: "GET",
           url: base_url+"index.php/Product/displayprodt",
           data: ({pid: pid}),
           success: function(response) {
             location.href = base_url+"index.php/product/displayprodt";
           }
        });
  });

Model:

public function displayprodt($pid){
        $this->db->select("*");
        $this->db->from("todaysdeal_products");
        $this->db->where("product_id",$pid);
        $query = $this->db->get();
        return $query->result();
    }
</div>
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