2016-11-11 00:38
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I am trying to check the result of an array_intersect as a regular array but it always returns true even if the array is empty.

      $lecturedayssplit1 = preg_split("/(?=[A-Z])/", "TF");
      $lecturedayssplit2 = preg_split("/(?=[A-Z])/", "MTh");
        if (count($lectolec) > 0) {
            echo "Yeah!!!";
        } else {
            echo "Nooo!";

$lectolec in the problem shouldn't return a count greater than 0 because there is no intersection between the two arrays. I also tried if (empty($lectolec)) but it also didn't work. Hopefully someone can help out. Thanks in advance!

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2条回答 默认 最新

  • dtlab08822 2016-11-11 00:55

    Because you are using a "zero-width positive lookahead" (?=[A-Z]) regex, it is matching an empty sequence in the beginning of each test. Therefore, array_intersect matches that empty sequence in both.

    You can use the flag PREG_SPLIT_NO_EMPTY to ignore those empty results.

    $lecturedayssplit1 = preg_split("/(?=[A-Z])/", "TF", -1, PREG_SPLIT_NO_EMPTY);
    $lecturedayssplit2 = preg_split("/(?=[A-Z])/", "MTh", -1, PREG_SPLIT_NO_EMPTY);
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  • dongmou1964 2016-11-11 00:54

    Never mind guys, I got it. I changed the conditional to if (count($lectolec) > 1) because it always has at least one count even if the array is empty

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