douna5529 2016-06-12 00:24
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使用$ .each JQUERY以引导程序形式显示加载程序数据

i'm trying to display json data loaded from php in a bootstrap form with one line but not working with me

here is JAVASCRIPT

var req_='getprosp&id='+trdata.IDP;
    $.ajax({
        type: "GET",
        url: "lib/read.php?req="+req_,
        contentType: "application/json; charset=utf-8",
        global: false,
        async: true,
        dataType: "json",
        success: function(data) {
            for (var i in data) {
                $('input[name="'+i+'"]').val(data[i]);
            }
            //$.each(data, function(key, val) {console.log(val) });
        }
    });

thanks for helping

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2条回答 默认 最新

  • doushi5752 2016-06-12 01:32
    关注

    worked with this:

                                var req_='getprosp&id='+trdata.IDP;
                        $.ajax({
                            type: "GET",
                            url: "lib/read.php?req="+req_,
    
                            contentType: "application/json; charset=utf-8",
                            global: false,
                            async: true,
                            dataType: "json",
                            success: function(data) {
    
                                $.each(data, function(key, val) {
                                    //console.log(val)
                                    var namef;
                                    for(namef in val){
                                        console.log(namef + " = " + val[namef]);
                                        $('input[name="'+namef+'"]').val(val[namef]);
                                    }
    
                                });
                            }
                        });
    
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