douyi1779 2016-09-15 14:22
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xml feed的代码无法正常工作

I'm trying to print an xml feed into my php page,but this code is not working correctly, and i have no idea why. It just shows the code as it is on the browser from xpath to ?> . Can anyone help me with this please

<html>
<head>
   <title>XML FEED</title>
 </head>
 <body>
   <ul>
   <?php
     $dom = simplexml_load_file("http://feeds.bbci.co.uk/news/rss.xml");
     foreach ($dom->xpath("/channel/item") as $item)
     {
        print "<li>";
        print $item->title;
        print "</li>";
     }
    ?>
  </ul>
</body>
</html>
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2条回答 默认 最新

  • duanjun7801 2016-09-15 20:45
    关注

    Consider adjusting your XPath with double forward slashes as channel is not the root element:

    foreach ($dom->xpath("//channel/item") as $item) {
        ...
    }
    

    Alternatively, use the root, rss, element in expression:

    foreach ($dom->xpath("/rss/channel/item") as $item) {
        ...
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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