dtr32221 2016-09-15 05:21
浏览 9

如何将MySQL行拆分为连接中每个表的单独变量

If I am fetching results from a JOIN query, how do I get separate variables for each table in the join per each row?

For example:

$result = $mysql->query(sprintf('SELECT *
    FROM `TableOne` one
    JOIN `TableTwo` two ON (one.TwoID = two.TwoID)
    JOIN `TableThree` three ON (one.ThreeID = three.ThreeID)
    WHERE one.OneID = %u',
    (int)$primary_key));
while ($row = $result->fetch_assoc()) {
    // Instead of $row, I want:
    // $one: all fields from TableOne
    // $other: all fields from TableTwo and TableThree
}
  • 写回答

1条回答 默认 最新

  • dongsui3297 2016-09-15 05:21
    关注

    Solution:

    function mysqli_fetch_assoc_per_table(mysqli_result $result, $instruction) {
        $row = $result->fetch_assoc();
        if (!$row) return false;
        $fields = $result->fetch_fields();
    
        $groups = array();
        foreach (explode(',', $instruction) as $arg) {
    
            $group = array();
            foreach (explode('|', $arg) as $table) {
                foreach ($fields as $field) {
                    if ($field->table == $table) {
                        $group[$field->name] = $row[$field->name];
                    }
                }
            }
    
            $groups[] = $group;
        }
    
        return $groups;
    }
    

    Usage:

    while (list($one, $other) = mysqli_fetch_assoc_per_table($result, 'one,two|three')) {
    
    }
    
    评论

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