empty（$ _ GET ['variable']）在变量没有值时阻止脚本

Question

I am writing quite a simple script that uses a GET parameter to define a variable in the script. So at the beginning of the script, I check that the GET parameter exists and that it's not empty (to avoid ...page.php?param=).

I wrote this piece of code (the parameter is named a) :

if (!isset($_GET['a']) || empty($_GET['a'])) {
    header("Location: https://..."); // redirect to home page
    die();
}

And it works when there is no GET parameter at all, but if there is either ?a or ?a=, then the page is just blank, even though I add an echo "some text";

I don't really understand what is going on. Could someone explain it to me?

Thank you :-)

EDIT : here is the whole code page:

<?php

if (!isset($_GET['a']) || trim($_GET['a']) == '' || $_GET['a'] == NULL) {
    header("Location: https://google.com");
    exit();
}

echo "hello";

So I should either redirect to Google.com or print "hello" but none of this happens.

Answer 1

A blank page is a classic example of a PHP error. You need to set up and use PHP error logging facility like so:

error_reporting(E_ALL);
ini_set('display_errors', 1);

At the very top of your page.

Rewriting your page I would do this:

error_reporting(E_ALL);
ini_set('display_errors', 1);
if (!isset($_GET['a']) || is_null($_GET['a'])) {
    header("Location: https://google.com");
    exit();
}

echo "hello";