PHP静态函数作为依赖注入的参数

Question

I'd like to call a static function of class A, in class B by passing it via Start.php as a parameter, but without including the ClassA.php into ClassB.php.

The reason I want to do this is because I have some client-specific logic, that i want to separate and call centrally and only when I really need it (index.php) without including it in the other files.

Let's say I've 3 files.

Start.php, ClassA.php, ClassB.php

ClassA.php

class A {

  public static function foo($param) {
    // do some special logic
    // and return either true or false
  }

}

ClassB.php

class B {

    function bar($var, $func) {
      foreach($var as $v) {
        if($func($var)) {
          echo 'OK';
        }
      }
    }

}

Start.php

require_once('ClassA.php');
require_once('ClassB.php');

class Start() {

  function init() {
    $b = new B();
    $test = array(1,2,3,4,5);
    $b->bar($test, ['A', 'foo']);
  }
}

Start::init();

So, Start depends on ClassA and ClassB, that's OK.

But I don't want ClassB to depend on ClassA.

When I do it like this, I get error, saying that Class A cannot be found.

Is that possible? Is that even considered as good practice?

Answer 1

I had to provide the full namespace to the function call, so:

$b->bar($test, ['my\
amespace\\A', 'foo']);