从php中的数组中读取文件

Question

I'm trying to open a directory, read just files with a .txt format and then display the contents. I've coded it out, but it doesn't do anything, although it doesn't register any errors either. Any help?

$dir = 'information';
    If (is_dir($dir)) {
    $handle = opendir($dir);
    } else {
    echo "<p>There is a system error</p>";
}
$entry=array();
        while(false!==($file = readdir($handle))) {
            if ( !strcmp($file, ".") || !strcmp($file, "..")) {
                }
                else if(substr($file, -4) == '.txt') {
                    $entry[] = $file;
                    }
            foreach ($entry as $txt_file) {
                    if(is_file($txt_file) && is_writable($txt_file))   {
                        $file_open = fopen($txt_file, 'r');
                        while (!feof($file_open)) {
                            echo"<p>$file_open</p>";    
                        }
                    }
                }
            }

Answer 1

Help is quite simple.

Instead

$dir = 'information';
If (is_dir($dir)) {
$handle = opendir($dir);
} else {
echo "<p>There is a system error</p>";
}

write (I am sorry for re-formatting of new lines)

$dir = 'information';
if(is_dir($dir))
{
    $handle = opendir($dir);
}
else
{
    echo "<p>There is a system error</p>";
}

because if has to be written only smallcaps, thus not If.

And the second part rewrite to (again, you may use your own formatting of new lines)

$entry=array();
$file = readdir($handle);
while($file !== false)
{
    if(!strcmp($file, ".") || !strcmp($file, ".."))
    {
    }
    elseif(substr($file, -4) == '.txt')
    {
        $entry[] = $file;
    }

    foreach ($entry as $txt_file)
    {
        if(is_file($txt_file) && is_writable($txt_file))
        {
            $file_open = fopen($txt_file, 'r');
            while(!feof($file_open))
            {
                echo"<p>$file_open</p>";    
            }
        }
    }
}

because PHP has elseif, not else if like JavaScript. Also I separated $file = readdir($handle) for possible source of error.

Code part

if(!strcmp($file, ".") || !strcmp($file, ".."))
{
}
elseif(substr($file, -4) == '.txt')
{
    $entry[] = $file;
}

should be shortened only to

if(substr($file, -4) == '.txt')
{
    $entry[] = $file;
}

because when if part is empty, then it is not neccessary.

That is all I can do for you at this time.