将PHP变量传递给Bash - 不止一个会破坏它

Question

Server 1 : php script

Server 1 sets the $mp3file variable which is received by the bash script on Server 2 as $1

The php script calls ssh2_exec like this (minus all the connection info) :

$stream = ssh2_exec($connection, "/root/incoming/test.sh ".escapeshellarg($mp3file)." &> /dev/null &");

Server 2 : bash script

test.sh (on server 2) contains a simple curl command :

curl -o /path/to/downloaded/file/$1 http://remotefilepath.com/$1

This all works perfectly, and the file is downloaded as expected.

But if I try to pass more than one variable like this :

$stream = ssh2_exec($connection, "/root/incoming/test.sh ".escapeshellarg($mp3file)." ".escapeshellarg($artwork)." &> /dev/null &");

The file is only partially downloaded.

Am I setting multiple variables the wrong way here which is breaking the &> /dev/null & command?

Answer 1

Ok after some messing around I found the only way I could get it working was by setting the escaped variables first :

$mp3file = escapeshellarg($mp3file);
$artwork = escapeshellarg($artwork);
$title = escapeshellarg($title);
$safeurl = escapeshellarg($safeurl);

Then passing them like this instead :

$stream = ssh2_exec($connection, "/root/incoming/test.sh $mp3file $artwork $title $safeurl &> /dev/null &");

I'm not sure that this is the only (or correct) way to do it, but it works.