dongwu8064
2016-07-30 05:15
浏览 75
已采纳

让app.yaml将目录路径转换为php脚本参数

Is it possible to have navigating to...

https://website.com/photos

...be the same as navigating to...

https://website.com/index.php?action=displayPhotos

...?


I have tried variations of the following without success...

- url: /photos
  script: /index.php?action=photos

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是否可以导航到...

   https://website.com/photos
nn

...与导航到...相同

 < 代码> https://website.com/index.php?action=displayPhotos
   
 
 

...


\ n

我尝试过以下各种变体而没有成功...

   -  url:/ photos 
 script:/index.php?action = photos \  n   
 
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1条回答 默认 最新

  • dtujfmfs06058 2016-08-23 17:11
    已采纳

    I left app.yaml as it was...

    - url: /(.+)
      script: index.php
      secure: always
    
    - url: /.*
      script: index.php  
      secure: always
    

    ...and used PHP to read from the URL.

    $directory = basename(parse_url($_SERVER["REQUEST_URI"], PHP_URL_PATH));
    if ($directory !== "" && $directory !== "index.php") {
        $action = $directory;
    }
    elseif (isset($_REQUEST["action"])) {
        $action = $_REQUEST["action"];
    }
    else {
        $action = "(unspecified)";
    }
    

    This facilitates script.js utilizing the less attractive form for passing one or more parameters, while site visitors can simply use slash plus text to indicate a single action or request.


    Credit to sanjary's answer to another question for reading the URL after the slash.

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