如何使用xpath提取解析href，src，alt

Question

i need to find the image link and a href . show href,img src, and alt tag.

here my code

$xpath = new DOMXPath('http,://.....');


foreach ($xpath->query('//a[@href]//img') as $img) {


echo '<a href=' .'"' .$img['href'] .'"' .'/>' .'<img src="' .$img['src']    .'"' .'alt="' .$img['alt'] .'"/>' .'</a>';



Catchable fatal error: Argument 1 passed to DOMXPath::__construct() must be an     
instance of DOMDocument, string given, called in

Can you help me??

Answer 1

You can use the following code

$dom = new DOMDocument();
libxml_use_internal_errors(true);
$dom->loadHTMLFile('http://example.com/');

$xpath = new DOMXpath($dom);

then use xpath to do whatever you want to do with it

Edited to get image src from link

# get the images inside a link
foreach ($xpath->query('//a[@href]//img') as $img) {

    # find all the links and images       
    for ($link = $img; $link->tagName !== 'a'; $link = $link->parentNode);

    $output[] = array(
        'href' => $link->getAttribute('href'),
        'src'  => $img->getAttribute('src'),
        'alt'  => $img->getAttribute('alt'),
    );
}