drpogkqqi536984960 2015-12-09 22:18
浏览 29

使用php文件中的查询生成的值

In a php file (that works) I generate one value from a database (being the last logged temperature)

<?php
$con = mysql_connect("localhost","datalogger","datalogger");

if (!$con) {
  die('Could not connect: ' . mysql_error());
}

mysql_select_db("datalogger", $con);

$result = mysql_query("SELECT * FROM datalogger.datalogger order by      date_time desc limit 1");

while($row = mysql_fetch_array($result)) {
  echo $row['temperature']. "
";
}

mysql_close($con);
?>

But in another php file I have to use this value at a place where there is now a fixed value value: [80]

How do I replace that value 80 with the value generated by the first php file ?

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2条回答 默认 最新

  • dqzow3859 2015-12-10 00:01
    关注

    It sounds like you need a helper function or class.

    function get_latest_temperature()
    {
        // Your db call
        return $temperature;
    }
    

    Helper class:

    class TemperatureModel
    {
       private $db_conn;
    
       public function __construct($db_conn)
       {
           $this->db_conn = $db_conn;
       }
       public function getLatestTemperature()
       {
           // Your db call
           return $temperature;
       }
       // Fictitious method
       public function getLowestEverTemperature()
       {
           // Another db call
           return $temperature;
       }
    }
    
    评论

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