Im following this guide to use aJax to upload an image, mainly so I can have a progress bar. But for some reason the PHP script doesn't seem to receive a file!
Here is my JavaScript:
function submitFile() {
var form = document.forms.namedItem("imageUpload");
var formData = new FormData(form);
var xhr = new XMLHttpRequest();
xhr.open("POST", "php/uploadImage.php", true);
xhr.onload = function(e) {
if (xhr.status == 200) {
console.log("uploaded!");
doc("imageResponse").innerHTML = xhr.responseText;
} else {
console.log("error!");
doc("imageResponse").innerHTML += "Error " + xhr.status + " occurred when trying to upload your file.<br \/>";
}
};
//Progress
/*
xhr.upload.onprogress = function(e) {
if (e.lengthComputable) {
var currentPercentage = Math.round(e.loaded / e.total * 100);
document.getElementById("imageUpload").innerHTML = "UPLOAD IMAGE " + currentPercentage + "%";
document.getElementById("imageUpload").style.backgroundSize = currentPercentage + "% 100%";
}
};
*/
//Send data
xhr.send(formData);
}
And here is my PHP file which receives the file:
<?php
session_start();
print_r($_FILES);
?>
Currently that PHP file is returning an empty Array... it should have my file!
Array ( )