du8589840 2015-06-29 21:11
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如何将php函数的输出添加到列表中

So i am trying to write code to do the following very basic thing:

*Take a number from the html input-form

*Take a counter, going from 0 to the input-number in a loop

*get the number as a list-item in the php-output, except if it is divisible by 3 or 5, which get ping and pong respectively as an output-value.

At the moment, this sadly does not work and all i get displayed is the tite & an error-message. Any and all help is very much appreciated!

Here the code from the html input-page:

<!DOCTYPE html>
<html>
<head>
    <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.1/css/bootstrap.min.css">
    <title>PHP Ping Pong Purified Perfection!</title>
</head>
<body>
    <div class="container">
        <h1>Geimme a number between 0 and 100 or you get a paddlin´!</h1>
        <form action="phpPingPong.php" method="post">
            <div class="form-group">
                <label for="inputNumber">The Number:</label>
                <input id="inputNumber" name="inputNumber" class="form-control" type="number">
            </div>
            <button type="submit" class="btn">Gimme the darn result already!</button>
        </form>
    </div>
</body>
</html>

Here´s the code from the php-page:

<?php 
    $inputNumber = $_GET["inputNumber"];
    $counter = 0;
    $outputMessage = "";

    function colorFate($inputNumber, $outputMessage)
    {
        if ($inputNumber < 100){

            for ( $counter == 1; $counter <= $inputNumber; $counter ++) {

                if ($counter % 5 === 0 && $counter % 3 === 0){
                    $outputMessage = "Ping-Pong";
                }

                else if ($counter % 3 === 0){
                    $outputMessage = "Ping";
                }

                else if ($counter % 5 === 0){
                    $outputMessage = "Pong";
                }

                else if ($counter % 5 != 0){
                    $outputMessage = $counter;
                }

                $outputMessage = "<li>"+ $outputMessage +"</li>";

                "#outputList".append ($outputMessage) ;


            }   
        }
        else{
            alert("Please follow the guidelines on what to enter!");
        }
    }

?>

<!DOCTYPE html>
<html>
<head>
    <title> PHPingPong </title>
</head>
<body>
    <h1>Read and Weep!</h1>
    <ul id="outputList">
    </ul>
</body>
</html>

Thanks again!

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1条回答 默认 最新

  • dougaxing8673 2015-06-29 21:16
    关注

    The First problem:- form method is POST and you use $_GET to retrieve the value in second page. change code like below:-

    $inputNumber = $_GET["inputNumber"]; to $inputNumber = $_POST["inputNumber"];

    Second one is :- $outputMessage = "<li>"+ $outputMessage +"</li>"; must be $outputMessage = "<li>".$outputMessage."</li>";

    Third is :- "#outputList".append ($outputMessage) ; it seems that you are mixing javascript code to php code. Don't do that.

    So your second page code must be like below:-

          <?php 
    $inputNumber = $_POST["inputNumber"];


    function colorFate($inputNumber)
    {

        $new_array = array();
        $outputMessage = "";
        if ($inputNumber < 100){

            for ( $counter = 1; $counter <= $inputNumber; $counter++) {

                if ($counter % 5 === 0 && $counter % 3 === 0){
                    $new_array['Ping-Pong'][$counter] = $counter;
                }else if ($counter % 3 === 0){
                    $new_array['Ping'][$counter] = $counter;
                }else if ($counter % 5 === 0){
                    $new_array['Pong'][$counter] = $counter;
                }else if ($counter % 5 != 0){
                    $new_array['nothing'][$counter] = $counter;
                }
            }
            return $new_array;  
        }
        else{
            alert("Please follow the guidelines on what to enter!");
        }
    }

?>

<!DOCTYPE html>
<html>
<head>
    <title> PHPingPong </title>
</head>
<body>
    <h1>Read and Weep!</h1>
    <?php $result = colorFate($inputNumber);?>
    <?php foreach($result as $key=>$value){
        echo "<ul><span>$key numbers are:-".implode(',',$value)."</ul>";
    }?>
</body>
</html>
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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