第二次访问时刷新网站[重复]

Question

This question already has an answer here:

• How do we control web page caching, across all browsers? 26 answers

I would like to "force-load" an instance of a page every time it's accessed.

The website in question is a "build your custom product"-kind of site and uses a multi-step form to guide customers through the steps of the product building. The client wants the site to be such that every time a user access the site, whether by direct url or by clicking on the "back" and "forward" buttons on the browser, it must refresh. In other words, no caching (right?).

I've tried to use the solutions I found on SO and on other websites, which mainly consisted of

header("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT");
header("Cache-Control: no-store, no-cache, must-revalidate");
header("Cache-Control: post-check=0, pre-check=0", false);
header("Pragma: no-cache");

But that didn't work.

So I tried my own solution:

$location = "/fabriquer/";
if(isset($_COOKIE['first_load']) && $_COOKIE['first_load'] == "true") {
    setcookie('first_load', 'false');
    header("Location: " . "http://" . $_SERVER['HTTP_HOST'] . $location);
} else {
    setcookie('first_load', 'true');
}

But that also seems to not be working properly. When I press the back button on my browser to get back on that site, the refresh does not happen, but the cookie is set to true/false in the second solution.

Any ideas?

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Answer 1

The only way you can get the browser to nto cache the page is to change the url every time. For instance append a random number or datetime as a param

$url = $url.'?ver='.rand(1,1000);

Add this to every url as you go from one page to another. I add a version number on mine. That way, whenever I update the site, everyone gets fresh copies.